Asolution is made initially with 0.200 m hio3 (kc = 0.17). once the equilibrium below is established, what is the equilibrium concentration of h* ions? hio3 (aq) = h+ (aq) + 103- (aq) 7 8 9 x 100

Answer : The concentration of hydrogen ion at equilibrium is 0.118 M

Solution :  Given,

Concentration (c) = 0.200 M

Equilibrium constant =

The equilibrium reaction is,

initially conc.       c           0         0

At eqm.                       

First we have to calculate the concentration of value of dissociation constant .

Formula used :

Now put all the given values in this formula ,we get the value of dissociation constant .

By solving the terms, we get

Now we have to calculate the concentration of hydrogen ion at equilibrium.

Therefore, the concentration of hydrogen ion at equilibrium is 0.118 M

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