Given that δh = −571.6 kj/mol for the reaction 2 h2(g) + o2(g) → 2 h2o(l), calculate δh for these reactions. (a) 2 h2o(l) → 2 h2(g) + o2(g)

Answer : The value of for the reaction is +571.6 kJ/mole.

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

Now we have to determine the value of for the following reaction i.e,

According to the Hess’s law, if we reverse the reaction then the sign of change.

So, the value for the reaction will be:

Hence, the value of for the reaction is +571.6 kJ/mole.

the correct answer is boyle

it is stable as it is in group 0 which have full outer shells of electrons