Two 0.75 amp loads are connected in parallel with a 2500 milliamperehour ni-cd battery. approximately how long can the battery provide power to the load?

Explanation:

It is given that two loads have 0.75 Ampere current each. And, they contain 2500 milli ampere per hour Ni-Cd battery.

As both the loads are connected in parallel. Hence, total current will be calculated as follows.

               I =

                 = 0.75 A + 0.75 A

                 = 1.5 A

                 =

                 = 1500 mA

Relation between time and capacity of battery is as follows.

             Capacity = Current × time (in hour)

therefore,        time =

                                =

                                = 1.667 hr

Thus, we can conclude that the battery provide power to the load up to 1.667 hours.

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year

i don't know people like to fight everywhere rip.