A) compute the total flux released from 1 g of spherical salt nanoparticles in water having an ssa of 100 m2/g.
b) assume that the nanoparticles diameter is constant, satp conditions and that the concentration of salt far away from the particles is always 0. how much g of nanoparticles would you need if the total flux remains constant and the nanoparticle diameter is 1 um?
c) how much g of material would you need if you replace the nanoparticles with nanofiber having an ssa of 100 m2/g (assuming that the length to diameter ratio of the nanofibers is very large)?
solubility in water = 35.9 g/100ml at 25°c
molar mass = 58.44 g/mol
= 2.165 g/cm3
diffusion coefficient of nacl = 1.33 × 10-5 cm2/sec

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

sure im new too!

explanation:

it is reliable if two scientists recorded it