Calculate the pressure (psig) at the bottom of a 7500 foot column of fluid for each of the following fluids:
a) water
b) drilling mud (sg = 1.3)
c) gas lift column (s. g. = 0.85)
d) natural gas column (sg = 0.6*) ‘*sg for natural gas is compared against air (density = 0.0765 lb/(cu ft))

Pressure at the botton of 7500 ft column is:

a) P (water) = 3256.508 psig

b) P (drilling mud) = 4229.035 psig

c) P (gas lift) = 18.092 psig

d) P (Natural gas) = 17.092 psig

Explanation:

hidrostatic pressure:

∴ density of fluid ( d.f ) ≡ Kg/m³

∴ aceleration o gravity ( g ) = 9.807 m/s²

∴ column height ( h ) = 7500 ft * ( m / 3.28084 ft ) = 2285.99 m

∴ atmospheric pressure (Po) = 101300 Pa ( Kg /m*s²)

specific gravity:

∴ d H2O = 997 Kg/m³

a) water:

⇒ P = ( 997 * 9.807 * 2285.99 ) + 101300

⇒ P = 22452844,88 Pa * ( psig / 6894.76 Pa ) = 3256.508 psig

b) Drilling Mud

⇒ SG = 1.3 = d.f / 997

⇒ d.f = 1296.1 Kg/m³

⇒ P = ( 1296.1 * 9.807 * 2285.99 ) + 101300

⇒ P = 29158182.16 Pa = 4229.035 psig

c) Gas lift column

⇒ SG = 0.85 = d.f / d.air (ref)

∴ d.air = 0.0765 Lb/ft³ = 1.23 Kg/m³

⇒ d.f = 1.23 * 0.85 = 1.0455 Kg/m³

⇒ P = ( 1.0455 * 9.807 * 2285.99 ) + 101300

⇒ P = 124738.755 Pa = 18.092 psig

d) Natural Gas column:

⇒ SG = 0.6 = d.f / 1.23

⇒ d.f = 0.738 Kg/m³

⇒ P = ( 0.738 * 9.807 * 2285.99 ) + 101300

⇒ P = 117845.003 Pa = 17.092 psig

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

he would use the colour black