How many liters of ammonia are required to change 34.9 l of nitrogen monoxide to nitrogen gas? assume 100% yield and that all gases are measured at the same temperature and pressure.

23.27 L

Explanation:

The balanced reaction of ammonia and nitrogen monoxide is shown below as:

4NH₃(g) + 6NO(g) ⇒ 5N₂(g) + 6H₂O(l)

Given that:

Volume of nitrogen monoxide = 34.9 L

Since, temperature and pressure are same, volume coefficients would be same as equation coefficients.

So,

6 L of nitrogen monoxide reacts with 4 L of ammonia.

1 L of nitrogen monoxide reacts with 4/6 L of ammonia.

34.9 L of nitrogen monoxide reacts with (4/6)*34.9 L of ammonia.

Amount of ammonia required = 23.27 L

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.