7. while prospecting in the north woods, joe found a gold nugget which had a density of 19.2 g/cm3. joe dropped the gold into water in a graduated cylinder, the water level increased by 15.0 ml. how many grams of gold did he have? (ans: 288 g)

m = 288 g

Explanation:

1) Data:

a) d = 19.2 g/cm³

b) ΔV water = 15.0 ml

c) m = ?

2) Principles and formula:

density = mass / volume

        d = m / v

The volume of water displaced, i.e. the increase in the level of water, is equal to the volume of the gold nugget submerged.The unit ml (mililiter) is equal to the unit cm³

3) Solution:

a) v = ΔV water = 15.0 ml = 15 cm³

b) d = m / v ⇒ m = d × v = 19.2 g/cm³ × 15 cm³ = 288 g.

The correct answer is d

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.