You have 100.0 ml of a solution of hydrochloric acid that has a ph of 3.00. you add 100.0 ml of water to this solution. what is the resulting ph of the solution?

3.30

Explanation:

Original volume of the HCl solution = 100.0 mL

pH of the solution = 3.00

Concentration of the hydrogen ions can be calculated as:

pH = -log[H⁺]

So,

3 = - log[H⁺]

[H⁺] =  10⁻³ concentration units.

For original acid solution:

C₁ = 10⁻³ , V₁ = 100 mL

For 10% acid solution :

C₂ = ? , V₂ = 200 mL  (100 mL of water is added to 100 mL of original solution)

Using  

C₁V₁ = C₂V₂

10⁻³×100 = C₂×200

C₂ = 0.5×10⁻³ concentration units.

So,

pH is :

pH = -log[H⁺] = -log(0.5×10⁻³) = 3.30

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o