Chemistry, 13.08.2019 03:30 tddreviews

4fecr2o7 + 8 k2co3 + o2 2 fe2o3 + 8 k2cro4 + 8 co2 how many grams of iron (ii) dichromate are required to produce 44.0 grams of carbon dioxide? how many grams of oxygen gas are required to produce 100.0 grams of ferric oxide? if 300.0 grams of iron (ii) dichromate react, how many grams of oxygen gas will be consumed? how many grams of iron (iii) oxide will be produced from 300.0 grams of ferrous dichromate?

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Answer from: meg7211

a)135.9 grams

b) 10 grams

c) 8.83g

d) 88.3g

Explanation:

the balanced reaction shows that four molecules of iron (II) dichromate will react with eight molecules of potassium carbonate and one molecule of oxygen to give two molecules of ferric oxide, eight molecules of potassium chormate and carbon dioxide each.

a) How many grams of iron (II) dichromate are required to produce 44.0 grams of carbon dioxide?

The molar mass of carbon dioxide = 44 g/mol

The molar mass of iron (II) dichromate = 271.8 g/mol

Thus as we need one mole of carbon dioxide we need to have half moles of iron (II) dichromate = 0.5 X 271.8 = 135.9 grams

b) How many grams of oxygen gas are required to produce 100.0 grams of ferric oxide?

The molar mass of ferric oxide =160 g/mol

the molar mass of oxygen = 32 g/mol

two moles of ferric oxide are obtained from one mole of oxygen

thus

320g of ferric oxide from 32 grams of oxygen

for 100g of ferric oxide the mass of oxygen required = 10 grams

c) If 300.0 grams of iron (II) dichromate react, how many grams of oxygen gas will be consumed?

The molar mass of iron (II) dichromate = 271.8 g/mol

the molar mass of oxygen = 32 g/mol

With four moles of iron (II) dichromate one mole of oxygen reacts

thus 4 X 271.8 grams of iron (II) dichromate reacts with = 32g of oxygen

hence 300 grams will react with =

$\frac{32X300}{4X271.8}=8.83g$

d) How many grams of iron (III) oxide will be produced from 300.0 grams of ferrous dichromate?

The molar mass of iron (II) dichromate = 271.8 g/mol

The molar mass of ferric oxide =160 g/mol

from 4 moles of iron dichromate two moles of ferric oxides are formed

thus

4 X 271.8 grams of iron dichromate will give = 2X160 g of ferric oxide

300 grams will give =

$\frac{2X160X300}{4X271.8}=88.3g$

Answer from: Quest

Ithink the answer is 56.

Answer from: Quest

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation:

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