Assume you are growing bacteria on a lipid medium that started at ph 7. the action of bacterial lipases should cause the ph of the medium to
a) increase. b) decrease. c) stay the same.

The correct answer is B) Decrease.

Explanation:

Lipases are enzymes in charge of descompose lipids in fatty acids and glycerol. This process allows the bacteria to obtain energy and metabolize the carbon source present in the medium. In relation to the pH, since lipases produce fatty acids, we can expect that the pH decreases, given the acid character of the fatty acids.

Therefore, the correct answer is B) decrease.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

what's the