The natural abundances of elements in the human body, expressed as percent by mass, are oxygen (o), 65 percent; carbon (c), 18 percent; hydrogen (h), 10 percent; nitrogen (n), 3 percent; calcium (ca), 1.6 percent; phosphorus(p), 1.2 percent; all other elements, 1.2 percent. calculate the mass in grams of each element in the body of a 62-kg person.

The mass of oxygen is 40300 g, hydrogen is 11160 g, nitrogen is 6200 g, calcium is 1860 g, phosphorus is 992 g and other elements is 744 g in the body of 62 kg person.

Explanation:

We are given:

Mass of body = 62 kg = 62000 g   (Conversion factor: 1 kg = 1000 g)

Mass percent of oxygen = 65 %

This means that 65 grams of oxygen is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of oxygen present is 65 grams.

So, in 62000 grams of human body, the mass of oxygen present will be =

Mass of oxygen present = 40300 g

Mass percent of hydrogen = 18 %

This means that 18 grams of hydrogen is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of hydrogen present is 18 grams.

So, in 62000 grams of human body, the mass of hydrogen present will be =

Mass of hydrogen present = 11160 g

Mass percent of nitrogen = 10 %

This means that 10 grams of nitrogen is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of nitrogen present is 10 grams.

So, in 62000 grams of human body, the mass of nitrogen present will be =

Mass of nitrogen present = 6200 g

Mass percent of calcium = 3 %

This means that 3 grams of calcium is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of calcium present is 3 grams.

So, in 62000 grams of human body, the mass of calcium present will be =

Mass of calcium present = 1860 g

Mass percent of phosphorus = 1.6 %

This means that 1.6 grams of phosphorus is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of phosphorus present is 1.6 grams.

So, in 62000 grams of human body, the mass of phosphorus present will be =

Mass of phosphorus present = 992 g

Mass percent of other elements = 1.2 %

This means that 1.2 grams of other elements is present in 100 grams of human body.

By applying unitary method, we get:

In 100 g of human body, the mass of other elements present is 1.2 grams.

So, in 62000 grams of human body, the mass of other elements present will be =

Mass of other elements present = 744 g

Hence, the mass of oxygen is 40300 g, hydrogen is 11160 g, nitrogen is 6200 g, calcium is 1860 g, phosphorus is 992 g and other elements is 744 g in the body of 62 kg person.

a non redox reaction occurs when there is not a transfer of electrons. for redox reactions, which are reduction-oxidation reactions, a change in the oxidation number occurs. elements that are reduced gain electrons, and elements that are oxidized lose electrons.

explanation:

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