You need to prepare an acetate buffer of ph 5.92 from a 0.819 m acetic acid solution and a 2.56 m koh solution. if you have 775 ml of the acetic acid solution, how many milliliters of the koh solution do you need to add to make a buffer of ph 5.92? the pka of acetic acid is 4.76.

V KOH = 247.939 mL

Explanation:

at the point of equilibrium:

mol CH3COOH = mol KOHfor weak acid system - strong bases...(1)

⇒ mol CH3COOH = 0.775L * 0.819 mol / L

⇒ mol CH3COOH = 0.634 mol CH3COOH(2)

replacing (2) in (1):

0.634 mol = V KOH * 2.56 mol / L

⇒ V KOH = 0.634 mol / (2.56 mol / L )

⇒ V KOH = 0.247939 L ( 247.939 mL )

what's the