What mass of 2-bromopropane could be prepared from 25.5 g of propene? assume a 100% yield of product.

78.46 grams of  2-bromopropane could be prepared from 25.5 g of propene

Explanation:

Moles of propene =

According to reaction, 1 mole of propene gives 1 mole of propane.

Then 0.6538 moles of bromo-propane will give:

78.46 grams of  2-bromopropane could be prepared from 25.5 g of propene.

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.