Consider the reaction: a (aq) ⇌ b (aq) at 253 k where the initial concentration of a = 1.00 m and the initial concentration of b = 0.000 m. at equilibrium it is found that the concentration of b = 0.357 m. what is the maximum amount of work that can be done by this system when the concentration of a = 0.867 m? (in kj)

The maximum amount of work that can be done by this system is -2.71 kJ/mol

Explanation:

Maximum amount of work denoted change in gibbs free energy during the reaction.

Equilibrium concentration of B = 0.357 M

So equilibrium concentration of A = (1-0.357) M = 0.643 M

So equilibrium constant at 253 K,

[A] and [B] represent equilibrium concentrations

When concentration of A = 0.867 M then B = (1-0.867) M = 0.133 M

So reaction quotient at this situation,

We know,  

where R is gas constant and T is temperature in kelvin

Here R is 8.314 J/(mol.K), T is 253 K, Q is 0.153 and is 0.555

So,

                           = -2710 J/mol

                            = -2.71 kJ/mol

the dependant variable is spilled water

the independent is the heat

it's all four options.