Asolution is prepared in which 0.00100 mol ni(no3)2 and 0.500 mol nh3 are dissolved in a total volume of 1.00 l. what is the concentration of ni(h2o)6 21 ions in the solution at equilibrium?

Explanation:

The given reaction will be as follows.

As are the separator ions. Hence, molarity of will be calculated as follows.

            Molarity of =

                                          = = 0.001 M

             Molarity of =

                                         = = 0.5 M

Hence, the molar ratio of and is .

So, it means that 0.001 moles of will require 0.001 × 6 = 0.006 moles of .

But in actual we are given that there are 0.5 mol of .

As molar ratio of and is 1:1.

Therefore, concentration of will be calculated as follows.

             Concentration of = }{/text{volume in liter}}" alt="Ni(H_{2}O)^{2+}_{6}}" />}{/text{volume in liter}}" />

                                           =

                                           = 0.001 M

Thus, we can conclude that the concentration of ions in the solution at equilibrium is 0.001 M.