Many power plants produce energy by burning carbon-based fuels, which also produces carbon dioxide. carbon dioxide is a greenhouse gas, so over-production can have negative effects on the environment. use enthalpy of formation data to calculate the number of moles of co2(g) produced per megajoule of heat released from the combustion of each fuel under standard conditions (1 atm and 25 °c).

2.54 mol CO2

Explanation:

To calculate the mol of carbon dioxide that will be generated by megajoule (MJ). First, we have to find the value of the formation enthalpy for the CO2 at standard conditions.

Remember that standard conditions are at 25°C and 1 atm.

Any physic chemistry book has the table of ΔHf°, I always use one name Levine's physic chemistry. You can trust its data.

Enthalpy of formation for CO2: -393.509 kJ/mol

As you can see this value means that for each 393.509 kJ liberate (that's indicated for the menus sing),  1 mol of CO2 is formed.

Let's write this using mathematic language:

393.509 kJ/ 1 mol CO2

The problem asks you to find how many mols are produced by 1 megajoule liberate, let's change megajoule to kilojoule.

1 megajoule (MJ) = 1000 kJ

1000 kJ x (1mol/ 393.509 kJ) = 2.54 mol CO2  

Remember don't use the negative value to make the calculus. The negative value just indicates that the heat is been released.

If you want to watch the mathematics details, go to the image attached.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"