How many ml. of 0.200 m pb(nos)2 solution are needed to obtain 0.875 grams of pb(no: )2?

Vsln=13.2mL

Explanation:

MwPb(NO3)2=331.2g/mol

⇒ Vsln = (1L Pb(NO3)2/0.200molPb(NO3)2) * (molPb(NO3)2/331.2gPb(NO3)2) * 0.875gPb(NO3)2

⇒  Vsln = 0.0132L (13.2mL)

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20 drops hope this