Daw the molecye as namol ) (2s)-2-amino-2-chloro ethan-1-ol 2) 1,1,3,3- letrapheny propan-2-amine 3) m, n,2,3,4,56hepha chlor ahil 33-amino- 3-phen 5) 3-amino- 3-puny penta-14-diene 6 ammonia

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

let that person have a turn to speak : )

2b2t

explanation:

2b2t

the correct answer would be b) volume versus temperature, because they are also directly proportional.