Calculate how many grams of the product form when 16.7 g of liquid bromine reacts with solid potassium. assume that there is more than enough of the solid potassium. 2 k(s) + br2(l) → 2 kbr(s)

49.7 grams of the product will be formed.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number of particles.

To calculate the moles, we use the equation:

Thus acts as limiting reagent as it limits the formation of product as potassium is in excess.

According to stoichiometry:

1 mole of reacts to give 2 moles of

Thus 0.21 moles of will react to give= moles of

Mass of

49.7 grams of the product will be formed.

it should be all of them because it asks if you included all of those in your answer

explanation:

i think the answer is terrae but not 100 percent sure. ▓▬▬ §