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Chemistry, 06.08.2019 19:10 logan12345677885675

Under certain conditions, the equilibrium constant of the reaction below is kc=1.7×10^−3. if the reaction begins with a concentration of 0.0546 m for each of sbcl3 and cl2 and a concentration of 0.0 m for sbcl5, what is the equilibrium concentration (in molarity) of cl2.
sbcl5(g)⇌sbcl3(g)+cl2(g)round your answer to the nearest ten-thousandth

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