The reaction between potassium chlorate and red phosphorus takes place when you strike a match on a matchbox. if you were to react 93.3 g of potassium chlorate with excess red phosphorus (p4), to produce tetraphosphorus decaoxide and potassium chloride, what mass of tetraphosphorus decaoxide would be produed?

The mass of tetraphosphorus decaoxide formed is 64.81g

Explanation:

To calculate the number of moles, we use the equation:

  ....(1)

Given mass of potassium chlorate = 93.3 g

Molar mass of potassium chlorate = 122.55 g/mol

Putting values in above equation, we get:

For the given chemical reaction:

Red phosphorus is given in excess . So, it is considered as an excess reagent and potassium chlorate is considered as a limiting reagent.

By Stoichiometry of the reaction:

10 moles of potassium chlorate reacts with 3 moles of tetraphosphorus decaoxide

So, 0.761 moles of potassium chlorate will react with = of tetraphosphorus decaoxide

Calculating the mass of tetraphosphorus decaoxide by using equation 1, we get:

Molar mass of tetraphosphorus decaoxide = 283.886 g/mol

Moles of tetraphosphorus decaoxide = 0.2283 moles

Putting values in equation 1, we get:

Hence, the mass of tetraphosphorus decaoxide formed is 64.81g

i believe it is c.) 1575 j.