Consider neon, a noble gas whose molecules consist of single atoms of atomic mass 0.02 kg/mol. what is the average kinetic energy of a neon atom when the gas is at a temperature of 370 k? avogadro’s number is 6.02 × 1023 mol−1 and boltzmann’s constant is 1.38 × 10−23 j/k. answer in units of j. question 5, chap 19, sect 4. part 2 of 3 10 points what is the root mean square speed of a neon atom under such conditions? answer in units of m/s.

Answer :

The average kinetic energy is,

The root mean square speed is,

Explanation:

(a) The formula for average kinetic energy is:

where,

k = Boltzmann’s constant =

T = temperature = 370 K

Now put all the given values in the above average kinetic energy formula, we get:

The average kinetic energy is,

(b) The formula used for root mean square speed is:

where,

= root mean square speed

k = Boltzmann’s constant =

T = temperature = 370 K

M = atomic mass = 0.02 kg/mole

= Avogadro’s number =

Now put all the given values in the above root mean square speed formula, we get:

The root mean square speed is,

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.