The brown gas no2 and the colorless gas n2o4 exist in equilibrium,2no2 n2o4.in an experiment, 0.625 mole of n2o4 was introduced into a 5.00 l vessel and was allowed to decompose until equilibrium was reached. the concentration of n2o4 at equilibrium was 0.0750 m. calculate kc for the reaction.0.0500.07500.100.1257.5

Answer : The value of for the reaction is, 7.5

Explanation :

Initial concentration of =

The balanced decomposition equilibrium reaction is,

Initial conc.     0.125          0

At eqm.          (0.125-x)       2x

The expression of equilibrium constant for the reaction will be:

Now put all the values in this expression, we get :

The concentration of at equilibrium = 0.0750 M

So, 0.125 - x = 0.0750

x = 0.05 M

Now put the value of 'x' in the above expression, we get:

Now we have to calculate the value of for the given reaction.

As we know that,

So,

Therefore, the value of for the reaction is, 7.5

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

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