The decomposition of nobr follows second order kinetics. the rate constant is found to be 0.556 m-1 s-1. if the initial concentration of nobr in the container is 0.25 m, how long will it take for the concentration to decrease to 0.025 m?

It will take 64.75 seconds for the concentration of NOBr to decrease to 0.025 M

Explanation:

The integrated rate law for decomposition of NOBr is -

where [NOBr] is concentration of NOBr after "t" time, is initial concentration of NOBr and k is rate constant

Here [NOBr] is 0.025 M, k is 0.556 and is 0.25 M

Plug in all the values in above equation-

                            or, t = 64.75

So it will take 64.75 seconds for the concentration to decrease to 0.025 M

c (diamond),

sio2 (quartz)