U-235 undergoes many different fission reactions. for one such reaction, when u-235 is struck with a neutron, ce-144 and sr-90 are produced along with some neutrons and electrons. how many neutrons and -particles are produced in this fission reaction?

Explanation:

A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.

The given reaction is

Now, we balance the mass on both reactant and product side as follows.

         235 + 1 =

           236 = 234 + x

            x = 236 -234

               = 2

So, now we balance the charge on both reactant and product side as follows.

              92 + 0 =

                92 = 96 - y

                  y = 4

Thus, we can conclude that there are 2 neutrons and 4 beta-particles are produced in the given reaction.

Therefore, reaction equation will be as follows.

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.