Consider the reaction between sulfite and a metal anion, x2-, to form the metal, x, and thiosulfate: 2 x2-(aq) + 2 so32- + 3 h2o(l) → 2 x(s) + s2o32- (aq) + 6 oh- for which eocell = 0.63. given that the eored for sulfite is -0.57 v, calculate eored for x. enter your answer to 2 decimal places

for X is -1.20 V

Explanation:

Oxidation: []

reduction:

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overall:

So,

or,

or,

So, for X is -1.20 V

The standard reduction potential of X is -1.20 V

Explanation:

For the given chemical equation:

The half reaction follows:

Oxidation half reaction:       ( × 2 )

Reduction half reaction:  

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the of the reaction, we use the equation:

We are given:

Putting values in above equation, we get:

Hence, the standard reduction potential of X is -1.20 V