At a temperature of 15 degrees c, a quantity of oxygen has a volume of 250 ml. if it’s temperature is raised to 45 degrees c, what will it’s volume be?

280 mL

Explanation:

Ideal gas law:

PV = nRT

Rearranging:

V / T = nR / P

At constant pressure:

V₁ / T₁ = V₂ / T₂

Substituting values:

250 / (15 + 273) = V / (45 + 273)

V = 276

Rounded to two significant figures, the volume will be 280 mL.

When using the ideal gas law, remember to always use absolute units for temperature, like Kelvin.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

it would be d. henry moseley

hope this !

and sorry if i'm late. have a good rest of your day! : d