Answer these questions fast! im on a time crunch right now

1st image, 17.79 g Mg(NO3)2

2nd image 1.47 mol NH3

3rd image Molar Mass Al(OH)3 = 78 g/mol

Explanation:

1st image

Molar Mass  Mg(NO3)2 = 148. 31 g/mol

0,12 mol Mg(NO3)2 x (148, 31 g Mg(NO3)2 / 1 mol Mg(NO3)2) = 17.79 gMg(NO3)2

2nd image

Molar Mass  NH3 = 17g/mol

25 g NH3 x ( 1 mol NH3/ 17 g NH3) = 1.47 mol NH3

3rd image

Molar Mass Al(OH)3 = 1 Al *(27) + 3 O * (16) + 3 H * (1) = 78 g/mol

the awnser is group 12