In a continuous steady-state condensation prog a continuous steady-state condensation process a vapor stream (100 mole/hr) containing benzene (0.4 mole fraction and water vapor a 150 and 1 atm pressure is coolca causa condensation. a liquid stream and a vapor stream leave the condenser at 1 atm pressure and 90c. the distribution of benzene and water between the phases may be assumed to be described by raoult's law. determine the amount of condensation in mole/hr and the amount of cooling in k r for this process. first solve the material balance equations, then solve the energy balance equation. you must contact an enthalpy table, as discussed in class, clearly stating your reference conditions and units. no table - no credit.

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answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol