How many grams of ice would be melted by the energy obtained as 16.1 g of steam is condensed at 100°c and cooled to 0°c? specific heat (ice) = 2.10 j/gºc specific heat (water) = 4.18 j/gºc heat of fusion = 333 j/g heat of vaporization = 2258 j/g 43.1 kg 36.4 kg 129 g 6.73 kg 20 g

129 g of ice would be melted by the energy obtained as 16.1

Explanation:

Total amount of heat obtained as 16.1 g of steam is condensed at 100 and cooled to 0 = [heat released during condensation of steam]+[heat released during cooling of steam to 0 ]

So, Total amount of heat obtained as 16.1 g of steam is condensed at 100 and cooled to 0 = [ = 43083.6 J

To melt 1 g of ice, 333 J of heat is required. Therefore 43083.6 J of heat would melt (43083.6/333) g of ice or 129 g of ice.

the answer for sodium is 0.186

the answer for rubidium is 0.251