For a solution of acetic acid (ch3cooh) to be called “vinegar,” it must contain 5.00% acetic acid by mass. if a vinegar is made up only of acetic acid and water, what is the molarity of acetic acid in the vinegar? the density of vinegar is 1.006 g/ml

Explanation:

1) Data:

a) Acetic acid CH₃COOH

b) molar mass of CH₃COOH: 60.052 g/mol

c) %: = 5.00%

d) d = 1.006 g/ml

e) M = ?

2) Formulae:

a) M = n of solute / V of solution in liters

b) n = mass in grams / molar mass

c) % = (mass of solute / mass of solution)×100

d) d = mass  / volume

3) Solution:

a) Assume a basis

b) Calculate the mass of that basis (1 liter of solution)

c) Calculate the mass of solute

        mass of solute = % × mass of solution / 100 = 5.00% × 1,006 g / 100

        mass of solute = 50.3 g

d) Calculate the number of moles of solute

e) Calculate molarity

i think that the answer is c