What is the ratio of acetic acid to acetate ion in solutions at ph 4, 6, 9 if the pka of acetate is 4.8?

At pH = 4, [Acetic acid]/[Acetate ion] = 6.3096

At pH = 6, [Acetic acid]/[Acetate ion] = 0.0631

At pH = 9, [Acetic acid]/[Acetate ion] = 6.3096×10⁻⁵

Explanation:

The pH of a buffer solution is calculated using Henderson Hasselbalch equation. The expression for the equation is:

For, Acetic acid (pKa = 4.8), Acetate will be its conjugate base.

To calculate the ratio of acetic acid and acetate ion in the solution.

Using the property of log that:

log(a/b) = -log(b/a)

The equation can be written as:

For pH =4 :

Thus, Taking anti log and solving as:

[Acetic acid]/[Acetate ion] = 6.3096

For pH =6 :

Thus, Taking anti log and solving as:

[Acetic acid]/[Acetate ion] = 0.0631

For pH =9 :

Thus, Taking anti log and solving as:

[Acetic acid]/[Acetate ion] = 6.3096×10⁻⁵

c is the answer because when something is left after something evaporates that shows the chemical change.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72