How long does it take light to travel across the width of a pb nucleus of radius 7.1 fm?

The light takes 4.73×10⁻²³ s to travel across the width of the Pb nucleus.

Explanation:

Given :

Radius of Pb nucleus = 7.1 fm

Also, The conversion of fm into m is shown below:

1 fm = 10⁻¹⁵ m

The radius of Pb nucleus = 7.1×10⁻¹⁵ m

The width of Pb nucleus (diameter) = 2× Radius of the nucleus

Thus,

Width of Pb nucleus = 2×7.1×10⁻¹⁵ m = 14.2×10⁻¹⁵ m

The Speed of light = 3×10⁸ m/s

The formula for Speed is shown below:

Time can be calculated from the above formula as:

Applying values in the above formula as:

Time = 4.73×10⁻²³ s

am i too late?

explanation:

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.