Excess ca(oh)2 is shaken with water to produce a saturated solution. the solution is filtered, and a 50.00 ml sample titrated with hcl requires 11.22 ml of 0.0983 m hcl to reach the end point. part a calculate ksp for ca(oh)2.

The for calcium hydroxide is

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is

We are given:

Putting values in above equation, we get:

The concentration of comes out to be 0.011 M.

The balanced equilibrium reaction for the ionization of calcium hydroxide follows:

The expression for solubility constant for this reaction follows:

Putting the values in above equation, we get:

Hence, the for calcium hydroxide is

Explanation:

The balanced chemical equation of the reaction is :

Ca(OH)2 + 2HCl → CaCl2 + 2 H20.

Ksp can be calculated by the following formula:

Ksp =  [Ca^{2+} ]+ [OH^{2-}].

Moles of HCl = Molarity × Volume of solution ( liters).

Moles of HCl can be calculated by multiplying 0.01122 (liters) ×0.0983

Moles of HCl = 0.0011 or  

The calculation of the concentration of Calcium hydroxide ( as starting with 50 ml) is :

.

.

Ksp =  [Ca^{2+} ]+ [2OH^{2-}].

Ksp =

Ksp =

Hence, the Ksp of calcium hydroxide is

am i too late?

explanation:

i think its 100

i hope this !