If it takes 22974 j to heat 96.5 g of a substance from 13.46°c to 73.86 °c, what is the specific heat of the substance?

The specific heat capacity, C, of the substance is 3.94 . To raise one gram of a substance by one degree Celsius, a specific amount of heat must be absorbed. This is called the specific heat of the substance. The higher the specific heat of a substance, the more energy is needed to increase its temperature and vice versa.

Further Explanation:

The specific heat capacity, C, of a substance is related to the amount of substance and the temperature change using the following equation

where

q = amount of heat absorbed (usually in J)

m = amount of substance (in g)

C = specific heat capacity (in )

T(f) = final temperature

T(i) = initial temperature.

To answer the problem, we sort the given information:

q = 22974 J (5 significan figures)

m = 96.5 g (3 significant figures)

C = ?

T(f) = 73.86 °C (4 significant figures)

T(i) = 13.46 °C (4 significant figures)

Then, to find C, rearrange the equation:

Plug in the values to the equation above to get the value of C.

Since the least number of significant figures in the given is 3, then the final answer must have 3 significant figures, too. Therefore,

Learn More:

1.Learn more about heat capacity

2.Learn more about calorimetry

3.Learn more about heat of reaction

Keywords: heat capacity, specific heat, calorimetry

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.