Calculate the change in entropy that occurs in the system when 4.20 mole of diethyl ether (\(\rm c_4h_6o\)) condenses from a gas to a liquid at its normal boiling point (\(34.6^{\circ} \rm \(\delta h_{vap}\) = 26.5 \(\rm kj/mol\)

Answer : The entropy change of the system is, 361.83 J/K

Solution :

Formula used :

where,

= entropy change of the system = ?

= enthalpy of vaporization = 34.6 kJ/mole

n = number of moles of diethyl ether = 4.20 mole

= normal boiling point =

Now put all the given values in the above formula, we get the entropy change of the system.

Therefore, the entropy change of the system is, 361.83 J/K

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explanation: