Which compounds give one singlet in the 1h nmr spectrum? ch3ch3 1461113dichloro22dibromo 1461123dimethyl2butene ch3―c≡c―ch3 ch2═chch═ch2 14611cyclohexadione 14611cyclopentane 14611123tribromopropane 14611ketone 14611ester

b. atoms in metallic solids are not arranged in a regular pattern

explanation:

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.