Asoft drink contains 11.5% sucrose (c12h22o11) by mass. how much sucrose, in grams, is contained in 355 ml (12 oz) of the soft drink? (assume a density of 1.04 g/ml.)
express your answer to three significant figures and include appropriate units.

42.5 g

Explanation:

Calculate the mass of the soft drink given the density and volume:

355 mL × 1.04 g/mL = 369.2 g

Now calculate the mass of sucrose given the percentage:

0.115 × 369.2 g = 42.46 g

Rounded to 3 significant figures, the mass is 42.5 g.

42.458 g of sucrose is contained in 355 mL (12 oz) of the soft drink

Explanation:

Volume of the soft drink = 355mL

Density = 1.04 g/mL

We know

Density = Mass / Volume

Rearranging the formula  

Mass of soft drink = Density × volume

So

Mass of sucrose

= 42.458 g  is the Answer

i believe the answer is 5,000