What is the specific latent heat of fusion of ice if it takes 863 kj to convert 4.6 kg of ice into water at 0 c?

Answer : The specific latent heat of fusion of ice is, 187.608 J/g

Explanation :

Formula used :

where,

Q = heat supply = 863 KJ = 863000 J

conversion used : (1 KJ = 1000 J)

m = mass of the substance = 4.6 Kg = 4600 g

conversion used : (1 Kg = 1000 g)

= specific latent heat of fusion = ?

Now put all the given values in the above formula, we get the specific latent heat of fusion of ice.

Therefore, the specific latent heat of fusion of ice is, 187.608 J/g

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.