Suppose that the concentration of ammonia produced in the reaction is 0.7 m and the concentrations of nitrogen and hydrogen used are 0.8 m and 0.02 m respectively. calculate the equilibrium constant for the reaction. start with the expression that follows this equation:
n2 (g) + 3h2 (> 2nh3 (g)
a. 0
b. 1 x 10^-6
c. 100,000
d. 1,000,000

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

i think so it’s will be b yes i believe its

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.