You analyze a sample of volatile liquid propyl acetate (c5h1002) by placing a small volume of it in a round-bottomed flask with a volume of 555.0 ml and an evacuated mass of 127.133 g. you submerge the flask in a water bath at 100.0°c and allow the volatile liquid to vaporize. you then cap the flask and remove it from the water bath. what will the mass of the 555.0-ml flask be after evaporation of the propyl acetate? (assume the pressure in the laboratory is 1.000 atm.)

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied