Consider the following reactions. reaction
(1): mn2 (aq) + so42−(aq) → mno4−(aq) + h2so3(aq) in acidic solution reaction
(2): ni2 (aq) + cl−(aq) → ni(s) + clo−(aq) in basic solution reaction
(3): mo(s) + n2o4(g) → moo2(s) + hno2(aq) in acidic solution reaction
(4): mno4−(aq) + cl−(aq) → mno2(s) + clo3−(aq) in basic solution
balance each equation under the specified conditions. (include states-of-matter under the given conditions in answer)

answer: you could do some invislibe ink.

explanation: i will tell you how to if u answer my question.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

the dependant variable is spilled water

the independent is the heat

i'm pretty sure its b i might be wrong though!