Calculate the solubility of nitrogen in water at an atmospheric pressure of 0.480 atm (a typical value at high altitude). atmospheric gas mole fraction kh mol/(l*atm) n2 7.81 x 10-1 6.70 x 10-4 o2 2.10 x 10-1 1.30 x 10-3 ar 9.34 x 10-3 1.40 x 10-3 co2 3.33 x 10-4 3.50 x 10-2 ch4 2.00 x 10-6 1.40 x 10-3 h2 5.00 x 10-7 7.80 x 10-4

Answer : The solubility of nitrogen in water at an atmospheric pressure will be,

Explanation :

First we have to calculate the partial pressure of nitrogen.

Formula used :

where,

= partial pressure of nitrogen = ?

= mole fraction of nitrogen =

= atmospheric pressure = 0.480 atm

Now put all the given values in the above formula, we get :

Now we have to calculate the solubility of nitrogen in water.

Formula used :

where,

= partial pressure of nitrogen = 0.375 atm

= solubility of nitrogen in water = ?

= Henry's constant =

Now put all the given values in the above formula, we get :

Therefore, the solubility of nitrogen in water at an atmospheric pressure will be,

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying