2.00 l of nitrogen gas at a temperature of 210 k are cooled down until the new volume is 1.25 l. if the pressure and number of gas particles do not change, to what temperature was the gas cooled?
131 k
1.19 x 10-2 k
7.62 x 10-3 k
336 k
answer

131 K

Explanation:

The only variables are volume and temperature, so we can use Charles' Law:

V1/T1 = V2/T2

Data:

V1 = 2.00 L; T1  = 210 K

V2 =  1.25 L; T2 = ?

Calculation:

2.00/210 = 1.25/T2

Multiply each side by the lowest common denominator (210T2)

2.00T2 = 1.25 ×210

2.00T2 = 262.5

       T2 = 262.5/2.00 = 131 K

The gas was cooled to 131 K.

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

10 years is the answer