Now let m react, and at time = 0, [m] = 0.102 m, a(545nm) = 0.491; at time = 30 seconds, a(545nm) = 0.404. what is the [m] at 30 seconds? what is the slope of the absorbance vs. [m] function? what is the (average) rate of the reaction during this time period.
if a new reaction was run leaving [n] the same, but beginning (time = 0) with [m] = 0.204 m, a(545nm) = 0.981. after 30 seconds, a (545 nm) is 0.807. what is the order of the reaction with respect to [m] ?

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Explanation:

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol