Ethanol has a kb of 1.22 degrees c/m and usually boils at 78.4 degrees celcius. how many mol of an nonionizing solute would need to be added to 47.84 g ethanol in order to raise the boiling point to 86.30?

0.3097 moles of an nonionizing solute would need to be added.

Explanation:

Molal elevation constant =

Normal boiling point of ethanol =

Boiling of solution =

Moles of nonionizing solute = n

Mass of ethanol (solvent) = 47.84 g

Elevation boiling point:

n = 0.3097 mol

0.3097 moles of an nonionizing solute would need to be added.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.