This problem has been solved! see the answerwhen 282. g of glycine (c2h5no2) are dissolved in 950. g of a certain mystery liquid x, the freezing point of the solution is 8.2c lower than the freezing point of pure x. on the other hand, when 282. g of sodium chloride are dissolved in the same mass of x, the freezing point of the solution is 20.0c lower than the freezing point of pure x. calculate the van't hoff factor for sodium chloride in x.

The van't Hoff factor for sodium chloride in X is 1.9 .

Explanation:

Mass of liquid x = 950 g = 0.950 kg

When 282 g of glycine are dissolved in 950 g of a certain mystery liquid X.

Depression in freezing point of the solution

Molality of the solution = m

The van't Hoff factor for glycine (non ionic) in liquid X= i =1

The value of molal depression constant for liquid X:

..(1)

Now 282. g of sodium chloride are dissolved in the same mass of X.

Depression in freezing point of the NaCl solution

Molality of the NaCl solution = m'

The van't Hoff factor for NaCl(ionic) in liquid X= i'

i = 1.9007 ≈ 1.9

The van't Hoff factor for sodium chloride in X is 1.9 .

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

58750.08068 is the answer i think