(need all boxes answered)
bicarbonate of soda (sodium hydrogen carbonate) is used in many commercial preparations. its formula is nahco3. find the mass percentages (mass %) of na, h, c, and o in sodium hydrogen carbonate. you may use whole numbers for the masses.
the mass of one mole of nahco3 is:

Answer & Explanation:

∴ The mass of 1.0 mol of NaHCO₃ = (no. of moles of NaHCO₃)(the molecular mass of NaHCO₃)

∴ The mass of 1.0 mol of NaHCO₃ = (1)(the molecular mass of NaHCO₃) = (the molecular mass of NaHCO₃).

∴ The mass of 1.0 mol of NaHCO₃ = (atomic weight of Na) + (atomic weight of H) + (atomic weight of C) + 3(atomic weight of O) = (23.0 g of Na) + (1.0 g of H) + (12.0 g of C) + 3(16.0 g of O) = (23.0 g of Na) + (1.0 g of H) + (12.0 g of C) + (48.0 g of O) = 84.0 g.

For Na:

The mass% of Na = (the mass of Na)/(the mass of  NaHCO₃) = (23.0 g)/(84.0 g) x 100 = 27.381%.

For H:

The mass% of H = (the mass of H)/(the mass of  NaHCO₃) = (1.0 g)/(84.0 g) x 100 = 1.19%.

For C:

The mass% of C = (the mass of C)/(the mass of  NaHCO₃) = (12.0 g)/(84.0 g) x 100 = 14.285%.

For O:

The mass% of O = (the mass of O)/(the mass of  NaHCO₃) = (48.0 g)/(84.0 g) x 100 = 57.143%.

The sum of % of elements = mass% of Na + mass% of H + mass% of C + mass% of O = 27.381% + 1.19% + 14.285% + 57.143% = 99.999% ≅ 100.0%.

Here's what I get.

Explanation:

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.