Given the following equation: > 8 co2 10 h20 2 с4н10 + 13 02 how many grams of c4h10 are needed to react with 35.1 grams of o2?

The mass of butane reacting with oxygen gas is 9.76 grams.

Explanation:

To calculate the number of moles, we use the equation:

   .....(1)

Given mass of oxygen gas = 35.1 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

For the given chemical reaction:

By stoichiometry of the reaction:

13 moles of oxygen gas is reacting with 2 moles of butane.

So, 1.096 moles of oxygen gas will react with = of butane.

Now, calculating the mass of butane from equation 1, we get:

Molar mass of butane = 58.12 g/mol

Moles of butane = 0.168 moles

Putting values in equation 1, we get:

Hence, the mass of butane reacting with oxygen gas is 9.76 grams.

it would be a gas formation