The value of δh° for the reaction below is -126 kj. the amount of heat that is released by the reaction of 10.0 g of na2o2 with water is kj. 2na2o2 (s) + 2h2o (l) → 4naoh (s) + o2 (g)

The enthalpy of the reaction for given amount of will be -8.064 kJ.

Explanation:

To calculate the number of moles, we use the equation:

Given mass of = 10 g

Molar mass of = 78 g/mol

Putting values in above equation, we get:

For the given chemical reaction:

By Stoichiometry of the reaction:

If 2 moles of produces -126 kJ of energy.

Then, 0.128 moles of will produce = of energy.

Thus, the enthalpy of the reaction for given amount of will be -8.064 kJ.